Search found 5 matches

by edysbe76
Thu Feb 20, 2014 12:31 pm
Forum: ARCH and GARCH Models
Topic: Variations on BEKK
Replies: 13
Views: 20014

Re: Variations on BEKK

TomDoan wrote:I can't diagnose a convergence problem without the data and full program. Did you successfully fit a TBEKK without asymmetry?

Dear Tom,

I got it! The TBEKK with/without asymmetry both are successful. Thank you very much for your help. :D
by edysbe76
Wed Feb 19, 2014 8:00 pm
Forum: ARCH and GARCH Models
Topic: Variations on BEKK
Replies: 13
Views: 20014

Re: Variations on BEKK

Since you're not using GARCH, the %NVAR variable (which dimensions the ZU VECTOR) is never set. Just add compute %nvar=4 before you start doing the diagnostics. Dear Tom, Thank you very much. I also try to estimate the Asymmetric Standard BEKK (Full BEKK) using GARCH instruction and also MAXIMIZE i...
by edysbe76
Wed Feb 19, 2014 10:14 am
Forum: ARCH and GARCH Models
Topic: Variations on BEKK
Replies: 13
Views: 20014

Re: Variations on BEKK

Dear Tom, Sorry to bother you again. Please help me with the following problem regarding the multivariate diagnostic test: ##MAT5 dec vect[series] zu(%nvar) do time=%regstart(),%regend() compute %pt(zu,time,%solve(%decomp(h(time)),%xt(u,time))) end do time ## MAT5. Needed Matrix with Dimensions 0 x ...
by edysbe76
Tue Feb 18, 2014 8:10 pm
Forum: ARCH and GARCH Models
Topic: Variations on BEKK
Replies: 13
Views: 20014

Re: Variations on BEKK

Dear Tom, Thank you for quick reply. Unfortunately I don't have RATS version 8.3. Yes you are right. Tsay does a set of univariate diagnostics and also multivariate diagnostics for the case of time-varying correlation models (tsayp524.rpf) but not full BEKK. Anyway, I refer to RATS v8 User's Guide f...
by edysbe76
Tue Feb 18, 2014 10:01 am
Forum: ARCH and GARCH Models
Topic: Variations on BEKK
Replies: 13
Views: 20014

Re: Variations on BEKK

Dear Tom, Is it possible to extend the BEKK Triangular model to include assymetry? Doing either one with the code you provided is easy, but together I haven't been able to figure it out. Yes, but, because of the forced p.s.d. nature of the calculation, the asymmetry in a BEKK gives you a (fundament...