Thanks
Is the value lamg=.11 used as an initial value for the estimation?
Search found 2 matches
- Mon Oct 13, 2014 10:04 am
- Forum: Examples and Sample Code
- Topic: Laubach and Williams RESTAT 2003
- Replies: 28
- Views: 96736
- Fri Oct 03, 2014 10:24 am
- Forum: Examples and Sample Code
- Topic: Laubach and Williams RESTAT 2003
- Replies: 28
- Views: 96736
Re: Laubach and Williams RESTAT 2003
Hi,
Can anyone tell me where the lamg estimate of 0.11 in the second stage comes from? It should be the ratio between two s.e but I dont find them.
[nonlin(parmset=peglam2) lamg=.11]
thanks
Can anyone tell me where the lamg estimate of 0.11 in the second stage comes from? It should be the ratio between two s.e but I dont find them.
[nonlin(parmset=peglam2) lamg=.11]
thanks