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power of a number

Posted: Thu Jan 16, 2014 10:44 am
by Aaron
Dear All,


Could you help me to compute 100^(0.2)? That is,

com aaa = 100^(0.2); dis aaa

this doesn't work. How can I get the power of a number less than one? Thank you.

Sincerely,

Aaron

Re: power of a number

Posted: Thu Jan 16, 2014 12:57 pm
by TomDoan
com aaa = 100^(0.2); dis aaa
2.51189
disp 2.51189^5
100.00071

Looks fine to me.