Dear All,
Could you help me to compute 100^(0.2)? That is,
com aaa = 100^(0.2); dis aaa
this doesn't work. How can I get the power of a number less than one? Thank you.
Sincerely,
Aaron
power of a number
Re: power of a number
com aaa = 100^(0.2); dis aaa
2.51189
disp 2.51189^5
100.00071
Looks fine to me.
2.51189
disp 2.51189^5
100.00071
Looks fine to me.