BAIPERRON—Multiple change point analysis

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elhampa
Posts: 16
Joined: Thu May 05, 2016 10:31 pm

Re: BAIPERRON—Multiple change point analysis

Unread post by elhampa »

Thank you Tom,

Is there a test to test for contegration and structural break at the same time?
TomDoan
Posts: 7814
Joined: Wed Nov 01, 2006 4:36 pm

Re: BAIPERRON—Multiple change point analysis

Unread post by TomDoan »

elhampa wrote:Thank you Tom,

Is there a test to test for contegration and structural break at the same time?
None that I'm aware of or at least not in the way that I think you mean it. Enders-Siklos is a test for cointegration with a specific form of break, which is in the loadings, not the cointegrating vector.
elhampa
Posts: 16
Joined: Thu May 05, 2016 10:31 pm

Re: BAIPERRON—Multiple change point analysis

Unread post by elhampa »

Thank you Tom,

How about the Gregory and Hanseon test "Residual-based tests for cointegration in models with regime shifts" Journal of Econometrics, 1996, vol. 70, issue 1, 99-126?
This test seems test for cointegration and break together. Please correct me if I am wrong.

And do you have any idea whether there is a more updated of this type?

Cheers
Elham
TomDoan
Posts: 7814
Joined: Wed Nov 01, 2006 4:36 pm

Re: BAIPERRON—Multiple change point analysis

Unread post by TomDoan »

No. That's a test for cointegration allowing for breaks (in the cointegrating vector). There is never any attempt to test whether there actually is a break.
elhampa
Posts: 16
Joined: Thu May 05, 2016 10:31 pm

Re: BAIPERRON—Multiple change point analysis

Unread post by elhampa »

Sorry Tom,

I am a confused.
Do you mean the Gregory and Hansen is test for break in a cointegrated system?

Regards
Elham
TomDoan
Posts: 7814
Joined: Wed Nov 01, 2006 4:36 pm

Re: BAIPERRON—Multiple change point analysis

Unread post by TomDoan »

No. Please read the description:

https://estima.com/ratshelp/gregoryhansenprocedure.html

It is assumed that there is a break at an unknown location in the (possible) cointegrating vector and it tests for cointegration under those assumptions. It does not test for a break. What you're looking for basically can't exist (logically). If the null is no cointegration (i.e. under root residuals) and no break, then the alternative is either cointegration or breaks but not necessarily both.
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